(use test) (define (variable? x) (symbol? x)) (define (same-variable? v1 v2) (and (variable? v1) (variable? v2) (eq? v1 v2))) (define (=number? exp num) (and (number? exp) (= exp num))) (define (make-sum a1 a2) (cond ((=number? a1 0) a2) ((=number? a2 0) a1) ((and (number? a1) (number? a2)) (+ a1 a2)) (else (list '+ a1 a2)))) (define (make-product m1 m2) (cond ((or (=number? m1 0) (=number? m2 0)) 0) ((=number? m1 1) m2) ((=number? m2 1) m1) ((and (number? m1) (number? m2)) (* m1 m2)) (else (list '* m1 m2)))) (define (sum? x) (and (pair? x) (eq? (car x) '+))) (define (addend s) (cadr s)) (define (augend s) (caddr s)) (define (product? x) (and (pair? x) (eq? (car x) '*))) (define (multiplier p) (cadr p)) (define (multiplicand p) (caddr p)) (define (deriv exp var) (cond ((number? exp) 0) ((variable? exp) (if (same-variable? exp var) 1 0)) ((sum? exp) (make-sum (deriv (addend exp) var) (deriv (augend exp) var))) ((product? exp) (make-sum (make-product (multiplier exp) (deriv (multiplicand exp) var)) (make-product (deriv (multiplier exp) var) (multiplicand exp)))) (else (error "unknown expression type: DERIV" exp)))) ;; ex 2.56 (define (exponentiation? x) (and (pair? x) (eq? (car x) '**))) (define (base exp) (cadr exp)) (define (exponent exp) (caddr exp)) (define (make-exponentiation b e) (cond ((=number? e 0) 1) ((=number? e 1) b) ((and (number? b) (number? e)) (expt b e)) (else (list '** b e)))) (define (deriv exp var) (cond ((number? exp) 0) ((variable? exp) (if (same-variable? exp var) 1 0)) ((sum? exp) (make-sum (deriv (addend exp) var) (deriv (augend exp) var))) ((product? exp) (make-sum (make-product (multiplier exp) (deriv (multiplicand exp) var)) (make-product (deriv (multiplier exp) var) (multiplicand exp)))) ((exponentiation? exp) (make-product (make-product (exponent exp) (make-exponentiation (base exp) (- (exponent exp) 1))) (deriv (base exp) var))) (else (error "unknown expression type: DERIV" exp)))) (test 0 (deriv '(** x 0) 'x)) (test 1 (deriv '(** x 1) 'x)) (test '(* 2 x) (deriv '(** x 2) 'x)) (test '(* 3 (** x 2)) (deriv '(** x 3) 'x)) (test '(* 3 (* 2 x)) (deriv '(* 3 (** x 2)) 'x)) (test '(* 3 (** (+ x 1) 2)) (deriv '(** (+ x 1) 3) 'x)) ;; ex 2.57 (define (augend s) (if (null? (cdddr s)) (caddr s) (cons '+ (cddr s)))) (define (multiplicand p) (if (null? (cdddr p)) (caddr p) (cons '* (cddr p)))) (test 6 (deriv '(+ (* 1 x) (* 2 x) (* 3 x)) 'x)) (test 6 (deriv '(* 2 3 x) 'x)) (test '(+ (* x y) (* y (+ x 3))) (deriv '(* x y (+ x 3)) 'x)) ;; ex 2.58a (define (make-sum a1 a2) (cond ((=number? a1 0) a2) ((=number? a2 0) a1) ((and (number? a1) (number? a2)) (+ a1 a2)) (else (list a1 '+ a2)))) (define (make-product m1 m2) (cond ((or (=number? m1 0) (=number? m2 0)) 0) ((=number? m1 1) m2) ((=number? m2 1) m1) ((and (number? m1) (number? m2)) (* m1 m2)) (else (list m1 '* m2)))) (define (sum? x) (and (pair? x) (eq? (cadr x) '+))) (define (addend s) (car s)) (define (augend s) (caddr s)) (define (product? x) (and (pair? x) (eq? (cadr x) '*))) (define (multiplier p) (car p)) (define (multiplicand p) (caddr p)) (test 4 (deriv '(x + (3 * (x + (y + 2)))) 'x)) ;; ex 2.58b (define (augend s) (if (null? (cdddr s)) (caddr s) (cddr s))) (define (multiplicand p) (if (null? (cdddr p)) (caddr p) (cddr p))) (test 4 (deriv '(x + (3 * (x + (y + 2)))) 'x)) (test 4 (deriv '((3 * ((y + 2) + x)) + x) 'x)) (test 4 (deriv '(x + 3 * (x + y + 2)) 'x)) ;; (test 4 (deriv '(3 * (x + y + 2) + x) 'x)) ;; the last test shows that precedence isn't taken care of yet, so ;; while the above is an elegant solution, it's not enough to merely ;; change the selectors